Question

Given the density of iron (Fe) is 7.87 g/cm3, determine the mass of iron (in grams) in a rectangle block with the dimensions of 12.5 in long, 3.50 in wide, and 2.50 in high. (1in = 2.54 cm).

Answer 1

`m=14,105.71 g Fe`

Step-by-step explanation:

Hello,

In this case, the first step is to compute the volume of the block considering the length, height and width:

`V=L * W * H =12.5 in* 3.50 in * 2.50 in =109.375 in^3`

Then, we compute the volume in cubic centimetres:

`V=109.375in^3* (16.3871 cm^3)/(1in^3) =1792.34cm^3`

Finally, as the density is given by:

`\rho =(m)/(V)`

We solve for the mass:

`m=\rho * V= 7.87(g)/(cm^3) * 1792.34 cm^3\\\\m=14,105.71 g Fe`

Best regards.