Question

HELP EASY PHYSICS QUESTION URGENT :))

A ball is kicked off the ground with a velocity of 15 m/s at an angle of 30° horizontally. What is the horizontal distance the ball travels before returning to the ground?

a.15.5 m

b.17.5 m

c.19.5 m

d.21.5 m

Answer 1

The horizontal distance the ball travels before returning to the ground is 19.5 m

Explanation:

Formula of range of horizontal distance =
`(u^2 Sin 2 \theta)/(g)`

Where u is the initial velocity

g is gravity

We are given that A ball is kicked off the ground with a velocity of 15 m/s at an angle of 30° horizontally.

So, u = 15 m/s

`\theta = 30^(\circ)`

g = 10

So, the horizontal distance the ball travels before returning to the ground =
`(15^2 Sin 2(30^(\circ)))/(10)=19.48 \sim 19.5 m`

Hence The horizontal distance the ball travels before returning to the ground is 19.5 m