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HELP EASY PHYSICS QUESTION URGENT :))

A ball is kicked off the ground with a velocity of 15 m/s at an angle of 30° horizontally. What is the horizontal distance the ball travels before returning to the ground?

a.15.5 m

b.17.5 m

c.19.5 m

d.21.5 m

User Xudre
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1 Answer

1 vote

Answer:

The horizontal distance the ball travels before returning to the ground is 19.5 m

Explanation:

Formula of range of horizontal distance =
(u^2 Sin 2 \theta)/(g)

Where u is the initial velocity

g is gravity

We are given that A ball is kicked off the ground with a velocity of 15 m/s at an angle of 30° horizontally.

So, u = 15 m/s


\theta = 30^(\circ)

g = 10

So, the horizontal distance the ball travels before returning to the ground =
(15^2 Sin 2(30^(\circ)))/(10)=19.48 \sim 19.5 m

Hence The horizontal distance the ball travels before returning to the ground is 19.5 m

User Daniel Yankowsky
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