Question

A cylindrical metal pipe has a diameter of 8.4 millimeters and a height of 10 millimeters. A hole cut out of the center has a diameter of 6 millimeters.

A smaller cylinder is cut out of a larger cylinder. The smaller cylinder has a diameter of 6 millimeters. The larger cylinder has a diameter of 8.4 millimeters. Both cylinders have a height of 10 millimeters.



What is the volume of metal in the pipe? Use 3.14 for and round the answer to the nearest tenth of a cubic millimeter.

Answer 1

B

Explanation:

Answer 2

`271.3 mm^3\\`

Explanation:

We have to find the volume of the hole and subtract it from the volume of the cylinder.

The volume of a cylinder is given as:

`V = \pi r^2h`

where r = radius

h = height

A cylindrical metal pipe has a diameter of 8.4 mm and a height of 10 mm.

Its radius is 4.2 mm. Therefore, its volume is:

`V = 3.14 * 4.2^2 * 10 = 553.9 mm^3`

A hole cut out of the center has a diameter of 6 mm. Its height is also 10 mm.

Its radius is 3 mm. Therefore, its volume is:

`V = 3.14 * 3^2 * 10 = 282.6 mm^3`

Therefore, the volume of metal in the pipe is:

`553.9 - 282.6 = 271.3 mm^3`