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Need help in b and c. show calculation pls.​

Need help in b and c. show calculation pls.​-example-1
User Virginia
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1 Answer

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√(16 - x^2) is defined only for -4 ≤ x ≤ 4, and is continuous over this domain, so


\displaystyle\lim_(x\to-4^+)√(16-x^2)=√(16-(-4)^2)=0

From the other side, the limit does not exist, because all x < -4 do not belong to the domain.

Taken together, the two-sided limit also does not exist.

User JxAxMxIxN
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