Question

In ΔJKL, the measure of ∠L=90°, KL = 6 feet, and JK = 7 feet. Find the measure of ∠K to the nearest tenth of a degree.

Answer 1

40.6 degrees

Explanation:

We know:

KL = 6

JK = 7

Angle L = 90 degrees

So JL is the hypotenuse, meaning we can find it with Pythagorean Theorem. This gets us :

`6^(2)+7^(2) = c^(2)\\c =√(85)`

We can find angle K with the following equation:

`sin(k) =(opposite)/(hypotenuse) = sin(k) = (6)/(√(85) ) = k = arcsin ( (6)/(√(85) )) = 40.6`

Answer 2

31

Explanation:

\cos K = Adj/Hyp = 6/7

cosK= 7/ 6

K=\cos^{-1}(6/7)

K=cos −1 ( 6/7 )

K=31.0027≈31