Question

Nitric acid (NO) reacts with oxygen gas to form nitrogen dioxide (NO2), a dark brown gas:

2NO(g) + O2(g) → 2NO2(g)

In one experiment, 0.886 mole of NO is mixed with 0.503 mol of O2.

Calculate which of the two reactants is the limiting reagent. (5 points)

Calculate also the number of moles of NO2 produced. (5 points)

What reactant is left over and how much of it is left over? (5 points)

Answer 1

Lim reag = NO .07 mole of O2 left over

Step-by-step explanation:

From the equation, you need twice as many moles of NO as O2

2 x moles O2 = 2 * .503 moles = 1.06 moles of NO needed....you do not have enough so this is the limiting reagent O2 will be left over

1/2 * .866 = .433 moles of O2 used .503 - .433 = .07 mole O2 leftover