Question

Help solve the above equation ​

Answer 1

`(1)/(27)`

Explanation:

`n^{-(2)/(3)}=9`

Rewrite:

`\frac{1}{\sqrt[3]{n^2}}=9\\\\9\sqrt[3]{n^2}=1`

Cube both sides:

`729n^2=1`

Divide both sides by 729:

`n^2=(1)/(729)`

Take the square root of both sides:

`n=\sqrt{(1)/(729)}=(1)/(27)`

Hope this helps!