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DEllAC AD=BE AB=16 BC=24
BE-? BD-?

DEllAC AD=BE AB=16 BC=24 BE-? BD-?-example-1
User JeremiahB
by
8.8k points

1 Answer

1 vote

Answer:

BE = 3.6 units

BD = 12.4 units

Explanation:

From the picture attached,

Since DE║AC, ΔBDE and ΔABC will be similar.

In these similar triangles corresponding side will be in the same ratio.


(BD)/(AB)=(BE)/(BC)


(AB-AD)/(AB)=(BE)/(BC)


1-(AD)/(AB)=(BE)/(BC)

1 -
(BE)/(AB)=(BE)/(BC) [Since AD = BE]

1 -
(BE)/(16)=(BE)/(24)

1 =
(BE)/(16)+(BE)/(24)

1 =
BE((3+2)/(48))

BE =
(18)/(5)

BE = 3.6 units

Therefore, AD = BE = 3.6 units [given]

Now BD = AB - AD

= 16 - 3.6

= 12.4 units

User Cyberixae
by
7.6k points

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