Question

In triangle ABC, Aat the top of the triangle, B at 90° and C at the third end, angle C = 21°, the hypotenus = 15m,find BC = y the unknown side

Answer 1

Explanation:

Law of sines: SinB/15 = SinA/BC

B = 90

A = 180-90-21=69°

BC= (15*SinA)/SinB = (15*sin69)/1 ≈ 14m