Question

The HCF of two numbers is 11, and their L.C.M is 368. If one number is 64, then the other number is ….

Answer 1

63.45

Explanation:

First, it should be noted that the question is incorrect because 64 can't be divided by 11 but assuming that the question is correct, the solution is as follows

Given

LCM = 368

HCF = 11

One number = 64

Required

The other number

Let both numbers be represented by m and n, such that

`m = 64`

From laws of HCF and LCM

The product of both numbers = Product of HCF and LCM

i.e.

`m * n = HCF * LCM`

By substituting 68 for m; 368 for LCM and 11 for HCF

`m * n = HCF * LCM` becomes

`64 * n = 368 * 11`

`64n = 4048`

Divide both sides by 64

`(64n)/(64) = (4048)/(64)`

`n = (4048)/(64)`

`n = 63.25`