Question

What is the equation of a line passing through (-6,5) and having a slope of 1/3?

Answer 1

y = (1/3)x + 7

Explanation:

Steps:

(y-y1)=m(x-x1) where m=slope

Using (x1,y1) is (-6,5):

1: (y-5)= (1/3)(x-(-6))

2: (y-5) = (1/3)(x+6)

3: y-5 = (1/3)x + 2 Distribute

4: y = (1/3)x + 7 Add 5 to both sides

Hope this helps.