Question

If the specific heat of gold is 0.13 J/gC, what is the amount of energy (heat) required to raise 30.0g of gold from 15 degrees Celsius to 41 degrees Celsius?

Answer 1

Answer: The amount of energy required is 101 Joules

Step-by-step explanation:

The quantity of heat required to raise the temperature of a substance by one degree Celsius is called the specific heat capacity.

`Q=m* c* \Delta T`

Q = Heat absorbed = ?

m= mass of gold = 30.0 g

c = specific heat capacity of gold =
`0.13J/g^0C`

Initial temperature of the water =
`T_i` = 15°C

Final temperature of the water =
`T_f` = 41°C

Change in temperature ,
`\Delta T=T_f-T_i=(41-15)^0C=26^0C`

Putting in the values, we get:

`Q=30.0g* 0.13J/g^0C* 26^0C`

`Q=101J`

The amount of energy required is 101 Joules