Answer:
Explanation:
Proportion of retired people under the age of 65 would return to work on a full-time basis if a suitable job were available = 60/100 = 0.6 = P
Null hypothesis: P ≤ 0.6
Alternative: P > 0.6
First, to calculate the hypothesis test, lets workout the standard deviation
SD = √[ P x ( 1 - P ) / n ]
where P = 0.6, 1 - P = 0.4, n = 500
SD = √[ (0.6 x 0.4) / 500]
SD = √ (0.24 / 500)
SD = √0.00048
SD = 0.022
To calculate for the test statistic, we have:
z = (p - P) / σ where p = 315/500 = 0.63, P = 0.6, σ = 0.022
z = (0.63 - 0.6) / 0.022
z = 0.03/0.022
z = 1.36
At the 2% level of significance, the p value is less than 98% confidence level, thus we reject the null hypothesis and conclude that more than 60% would return to work.