Answer:
The critical value of t =3.012
Explanation:
Solution
Recall that:
Bruce a store owner put together information on random sales of = 14 days
A significant level of =0.5%
The mean revenue per day = 65 dollars
Now,
We find he critical values using the partial t-table stated above
Thus,
The degree of freedom is given below:
n -1 = 14
14-1 =13
For a 0.005 level and right tailed test and with a 13 degree of freedom, the critical value of t =3.012.