Question

A 41 turn rectangular coil of dimensions 5.00 cm ✕ 10.0 cm is allowed to fall from a position where B = 0 to a new position where B = 0.520 T and the magnetic field is directed perpendicular to the plane of the coil. Calculate the magnitude of the average emf that is induced in the coil if the displacement occurs in 0.330 s.

Answer 1

Step-by-step explanation:

We have,

Number of turns in a coil is 41

Dimensions of a rectangular coil is 5 cm by 10 cm

Initial magnetic field is 0 and new field is 0.52 T. The magnetic field is directed perpendicular to the plane of the coil.

It is required to find the magnitude of the average emf that is induced in the coil if the displacement occurs in 0.330 s. According to Faraday's law,

`E=(-d\phi)/(dt)`

`\phi` = magnetic flux

`E=(-d(NBA))/(dt)\\\\E=NA(-(B_f-B_i))/(dt)\\\\E=41* 0.005* ((0.52))/(0.33)\\E=0.32\ V`

So, the magnitude of induced emf is 0.32 V.