Question

Two parallel wires are separated by 5.60 cm, each carrying 2.65 A of current in the same direction. (a) What is the magnitude of the force per unit length between the wires? N/m (b) Is the force attractive or repulsive? attractive repulsive

Answer 1

Step-by-step explanation:

It is given that,

The separation between two parallel wires, r = 5.6 cm = 0.056 m

Current in both the wires is 2.65 A

(a) We need to find the magnitude of the force per unit length between the wires. It can be given by :

`(F)/(l)=(\mu_o I_1I_2)/(2\pi r)\\\\(F)/(l)=(4\pi * 10^(-7)* 2.65* 2.65)/(2\pi * 0.056)\\\\(F)/(l)=2.5* 10^(-5)\ N/m`

(b) As the current is in same direction, the wires will attract each other.