Question

Not really sure how to do this

Answer 1

Explanation:

`\begin{bmatrix}6x=3y-7\\ 9y-18x-9=0\end{bmatrix}\\\mathrm{Isolate}\:x\:\mathrm{for}\:6x=3y-7:\quad x=(3y-7)/(6)\\6x=3y-7\\\mathrm{Divide\:both\:sides\:by\:}6\\(6x)/(6)=(3y)/(6)-(7)/(6)\\Simplify\\x=(3y-7)/(6)\\\mathrm{Subsititute\:}x=(3y-7)/(6)\\\begin{bmatrix}9y-18\cdot (3y-7)/(6)-9=0\end{bmatrix}\\\mathrm{Refine\:}9y-18(3y-7)/(6)-9=0\\12=0\\12=0\:\mathrm{\:is\:false,\:therefore\:the\:system\:of\:equations\:has\:no\:solution}\\No\:Solution`

I hope this is what you wanted