Question

516 mL of a 3.82 M sodium sulfate (Na2S04) solution is diluted with 0.875 L of water. What is the new concentration in molarity?

Answer 1

Molarity =
`1.4mol/L`

Step-by-step explanation:

Molarity provides the number of moles of solute per liter of solution (moles/Liter). It is a means by which concentration of solution is measured.

SEE THE ATTACHMENT BELOW FOR STEP BY STEP SOLUTION.

Answer 2

1.42 M

Step-by-step explanation:

In this case have a dilution problem, therefore we need to use the dilution equation:

`C_1*V_1=C_2*V_2`

What values we have?

`C_1=3.82M`

`V_1=526mL(0.516L)`

`C_2=?`

`V_2=?`

Now, we can calculate
`V_2` if we add the volumes, so:

`0.516~L+~0.875~L=1.391~L`

So,
`V_2=1.391~L`

We can plug the values in the equation:

`3.82~M*0.516~L=C_2*1.391~L`

`C_2=(3.82~M*0.516~L)/(1.391~L)`

`C_2=1.42~M`

I hope it helps!