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Find the number of unique permutations of the letters in the word: ONGOING

User BoRRis
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1 Answer

3 votes

Answer:

The Number of unique permutation is 6,615

Explanation:

This particular permutation deals with words that have repeated letters.

Given word = "ONGOING"

the formula for the permutation is


= (n!)/(mA! mB!.....mZ!)

where n is the amount of letters in the word, and m A , m B , ... , m Z are the occurrences of repeated letters in the word. Each m equals the amount of times the letter appears in the word.

So in the word "ONGOING"

n= 7

mO= 2

mN= 2

mG=2


permutations = (7!)/(2!2!2!) \\\\permutations= (7*6*5*4*3*2*1)/((2*1)*(2*1)*(2*1))


permutations= (52920)/(8) \\permutation = 6,615

User Leoa
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