195k views
3 votes
In ΔXYZ, the measure of ∠Z=90°, the measure of ∠X=65°, and ZX = 4.8 feet. Find the length of YZ to the nearest tenth of a foot.

1 Answer

3 votes

Answer:

10.3

Explanation:

\text{SOH-CAH-TOA}

SOH-CAH-TOA

\tan X = \frac{\text{opposite}}{\text{adjacent}}=\frac{x}{4.8}

tanX=

adjacent

opposite

=

4.8

x

\tan 65=\frac{x}{4.8}

tan65=

4.8

x

4.8\tan 65=x

4.8tan65=x

Cross multiply.

x=10.2936\approx \mathbf{10.3}\text{ feet}

x=10.2936≈10.3 feet

Type into calculator and round to the nearest tenth of a foot.

X

Y

Z

4.8

10.3

(adjacent to ∠X)

(opp. of ∠X)

(hypotenuse)

65°

User MarLeo
by
7.9k points