Question

weather balloon is filled with helium to a volume of 340 L at 30 ∘C and 751 mmHg . The balloon ascends to an altitude where the pressure is 495 mmHg and the temperature is -27 ∘C.What is the volume of the balloon at this altitude?

Answer 1

Answer: Thus the volume of the balloon at this altitude is 419 L

Step-by-step explanation:

Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.

The combined gas equation is,

`(P_1V_1)/(T_1)=(P_2V_2)/(T_2)`

where,

`P_1` = initial pressure of gas = 751 mm Hg

`P_2` = final pressure of gas = 495 mm Hg

`V_1` = initial volume of gas = 340 L

`V_2` = final volume of gas = ?

`T_1` = initial temperature of gas =
`30^oC=273+30=303K`

`T_2` = final temperature of gas =
`-27^oC=273-27=246K`

Now put all the given values in the above equation, we get:

`(751* 340)/(303)=(495* V_2)/(246)`

`V_2=419L`

Thus the volume of the balloon at this altitude is 419 L