Question

Body 1 has a mass m, and its moving in a circle with a radius r at a speed v. It has a centripetal force. F acting on it. If body 2 has a mass 2m and its moving in a circle of radius 4r at a speed 4v, what is the centripetal force acting on it

Answer 1

The centripetal force on body 2 is 8 times of the centripetal force in body 1.

Step-by-step explanation:

Body 1 has a mass m, and its moving in a circle with a radius r at a speed v. The centripetal force acting on it is given by :

`F=(mv^2)/(r)`

Body 2 has a mass 2m and its moving in a circle of radius 4r at a speed 4v. The centripetal force on body 2 is :

`F'=(2m* (4v)^2)/(4r)\\\\F'=(2m* 16v^2)/(4r)\\\\F'=8(mv^2)/(r)\\\\F'=8F`

So, the centripetal force on body 2 is 8 times of the centripetal force in body 1.