Question

Solve the pair of simultaneous equation
2-4(3x-y)=8(4-y)-39x and 8(4-y)-39x=6(y-x)

Answer 1

X = -(146/123) , Y = 21/41

Explanation:

• 2-4(3x-y) = 8(4-y)-39x

2-12x-4y = 32-8y-39x

39x-12x+8y-4y = 32-2

27x+4y = 30

27x+4y-30 = 0

• 8(4-y) -39x = 6(y-x)

32-8y-39x = 6y-6x

32-8y-6y-39x+6x = 0

-33x-14y+32 = 0