Question

Prove that:
please do it fast​

Answer 1

Explanation:

`A+B=\theta\\B=\theta-A\\sin B=sin (\theta-A)\\sin A=\lambda[sin \theta cos A-cos \theta sin A]\\sin A[1+\lambda cos \theta]=cos A(\lambda sin \theta) \\(sin A)/(cosA) =(\lambda sin \theta)/(1+ \lambda cos \theta) \\`

`tan A=(\lambda sin \theta )/(1+ \lambda cos \theta )`