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What is The true solution to In 20 +in 5=2in x?

1 Answer

3 votes

Answer:

x = 10

Explanation:

Combining the logarithms, you have ...

ln(20·5) = ln(x²)

100 = x² . . . . . take the antilogs

10 = x . . . . . . . take the positive square root

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Alternate solution

ln(2·2·5) +ln(5) = 2·ln(x) . . . . . . . factor 20

2ln(2) +ln(5) +ln(5) = 2·ln(x) . . . . rearrange ln(20)

ln(2) +ln(5) = ln(x) . . . . . . . . . . . . divide by 2

ln(10) = ln(x) . . . . . . . . . . . . . . . . combine logs on the left

10 = x

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These solutions make use of the rules of logarithms ...

ln(ab) = ln(a) +ln(b)

ln(a²) = 2·ln(a) . . . . . same as the first rule for a=b

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