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suppose the acceleration function of an object moving along a line is given by a(t) =0.2t. find the position of the object if you know the initial velocity was v(0) =-3 and initial position was s(0) =1

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Answer:

See below

Explanation:

sf = s0 + v0 t + 1/2 at^2

1 + (-3)t + 1/2 (.2t) t^2 ( weird acceleration value)

s = 1 -3t + .1 t^3 You will need a 't' value to determine the position

User Martin Lund
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