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Given sin thata = 2/5 and 0° < thata < 90°. find sin 2 thata​

User CCKx
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2 Answers

7 votes

Answer:

C

Explanation:

Edge2021

User Sam YC
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4 votes

Recall the double angle identity:


\sin2\theta=2\sin\theta\cos\theta

With
\theta measuring between 0º and 90º, we know
\cos\theta>0. So from the Pythagorean identity, we get


\sin^2\theta+\cos^2\theta=1\implies\cos\theta=√(1-\sin^2\theta)=\frac{√(21)}5

Then


\sin2\theta=2\frac25\frac{√(21)}5=(4√(21))/(25)

User Latlio
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