Question

Complete the table of values fory=2x^2+x

Answer 1

By using this quadratic function
`y=2x^2+x`, the table of values should be completed as follows;

x -2 -1 0 1 2

y 6 1 0 3 10

In order to use this quadratic function
`y=2x^2+x` to determine the missing values in the table, we would have to substitute each of the values of x (x-values) into the quadratic function and then evaluate as follows;

When the value of x is -2, the output value for the quadratic function is given by;

`y=2x^2+x\\\\y=2(-2)^2+(-2)\\\\y=8-2`

y = 6

When the value of x is 0, the output value for the quadratic function is given by;

`y=2x^2+x\\\\y=2(0)^2+(0)\\\\y=0+0`

y = 0

When the value of x is 2, the output value for the quadratic function is given by;

`y=2x^2+x\\\\y=2(2)^2+(2)\\\\y=8+2`

y = 10

Complete Question:

Complete the table of values for
`y=2x^2+x`.

Answer 2

Complete question:

y = 2x² + 2x - 3

x = -2 -1 0 1 2

Answer:

Complete table of values

x: -2 -1 0 1 2

y: 1 -3 -3 1 9

Explanation:

Given;

y = 2x² + 2x - 3

To complete the table of values of the equation above, we substitute the value of x into the given equation and solve for y.

when, x = -2

y = 2(-2)² + 2(-2) - 3

y = 8 - 4 - 3

y = 1

when x = -1

y = 2(-1)² + 2(-1) - 3

y = 2 - 2 - 3

y = -3

when x = 0

y = 2(0)² + 2(0) - 3

y = 0 - 0 - 3

y = -3

when x = 1

y = 2(1)² + 2(1) - 3

y = 2 + 2 - 3

y = 1

when x = 2

y = 2(2)² + 2(2) - 3

y = 8 + 4 - 3

y = 9

Complete table

x: -2 -1 0 1 2

y: 1 -3 -3 1 9