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What are the zeros of (fx) =x^2-10x+25​

User Sgraffite
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1 Answer

7 votes

Answer:

Zero of the function f(x) is x = 5

Explanation:

Given function is f(x) = x² - 10x + 25

For zeros or x-intercepts of this function,

Put f(x) = 0

x²- 10x + 25 = 0

x² - 2(5)x + 5² = 0

(x - 5)² = 0 [Since, a² - 2ab + b² = (a - b)²]

x = 5

Therefore, x = 5 will be the zero of the given function.

User Edgar Froes
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