Question

Calculate the pH of 0.65 M H2SO4 (sulfuric acid) solution? (Ka2: 1.1x10-2)

Answer 1

Step-by-step explanation:

.65 M H₂SO₄

H₂SO₄ ⇄ 2H⁺ + SO₄⁻²

C(1-x) 2xC xC

(2xC)². xC /C( 1- x ) = 1.1 x 10⁻²

4 x³C² = 1.1 x 10⁻²

4 . x³ .65² = 1.1 x 10⁻²

x³ = .0065 = 6.5 x 10⁻³

x = 1.867 x 10⁻¹

H⁺ ion concentration =

2xC = 2 x 1.867 x 10⁻¹ x .65

= .2427

pH = - log ( .2427 )

= 0 .615 .