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Mr. Ray wanted to measure the height of a light post. He placed a mirror on the ground 32 feet from the light post, then walked backwards until he was able to see the top of the light post. His eyes were 6 feet above the ground and he was 9 feet from the mirror. Using similar triangles, find the height of the light post to the nearest tenth of a foot.

Mr. Ray wanted to measure the height of a light post. He placed a mirror on the ground-example-1
User Mzafer
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1 Answer

5 votes

Answer:

Option (2) is the answer.

Explanation:

From the figure attached,

AB represents the length of Mr. Ray, ED represents the light post and the mirror was placed at point C.

Here AB = d = 6 feet

CD = w = 32 feet

BC = f = 9 feet

Since both the triangles ABC and EDC are similar, their corresponding sides will be in the same ratio.


(AB)/(DE)=(BC)/(CD)


(6)/(h)=(9)/(32)

h =
(6* 32)/(9)

h = 21.33 feet

h ≈ 21.3 feet

Therefore, height of the light post is 21.3 feet.

Option (2) is the answer.

Mr. Ray wanted to measure the height of a light post. He placed a mirror on the ground-example-1
User Abuharsky
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