Step-by-step explanation:
0,147 mol of CuBr2 equil 224 g/mol x 0.147 mol =33 gram
In 1 L solution dissolved 33 g of salt, but we want to get 13.9 g of salt
therefore, 13.9 g will be in the aqueous solution of volume 0.42 L or 420 mL
( 13.9 / 33 = 0.42 L)