Question

Suppose that a program's data and executable code require 1,024 bytes of memory. A new section of code must be added; it will be used with various values 70 times during the execution of a program. When implemented as a macro, the macro code requires 73 bytes of memory. When implemented as a procedure, the procedure code requires 132 bytes (including parameter-passing, etc.), and each procedure call requires 7 bytes. How many bytes of memory will the entire program require if the new code is added as a procedure? 1,646

Answer 1

The answer is 1646

Step-by-step explanation:

The original code requires 1024 bytes and is called 70 times ,it requires 7 byte and its size is 132 bytes

1024 + (70*7) + 132 = 1024 + 490 +132

= 1646