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The function f (t) =-16t^2 = 576 represents the height of a freely falling ballast bag that starts from rest on a ballon 576 feet above the ground. After how many seconds t does the ballast bag hit the ground.

User Vitor Reis
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1 Answer

1 vote

Answer:

The ballast bag hits the ground after 6 seconds.

Explanation:

Suppose there was a small typing mistake.

The height of the ball, after t seconds, is given by the following equation:


f(t) = -16t^(2) + 576

After how many seconds t does the ballast bag hit the ground.

This is t for which f(t) = 0. So


f(t) = -16t^(2) + 576


-16t^(2) + 576 = 0


16t^(2) = 576


t^(2) = (576)/(16)


t^(2) = 36


t = \pm √(36)

Time is a positive measure, so


t = 6

The ballast bag hits the ground after 6 seconds.

User Christopher Martin
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