Answer:
Moment of inertia at distance L / 2 from center
I1 = M (L / 2)^2 = M L^2 / 4
I2 = M (L / 6)^2 = M L^2 / 36 at a distance of L / 6
I (1/2 rod) = I1 + I2 = M L^2 (1/4 + 1/36) = M L^2 (9 + 1)/ 36 = 5/ 18 M L^2
I for entire rod = 2 I (1/2 rod) = 5 / 9 M L^2