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2 votes
Probability
0
1/2
1/5
1??​

Probability 0 1/2 1/5 1??​-example-1
User Keyah
by
5.7k points

1 Answer

4 votes

Answer:

1

Explanation:

Total number of portions = 10

unshaded portion= 5

number of even numbers =

probability of unshaded portion = 5/10 = 1/2

probability of even number = 5/10 = 1/2

Probability of landing on unshaded or even portion= probability of landing on unshaded portion + probability of landing on even number = 1/2 + 1/2 = 1

User Imagist
by
4.9k points