Question

In a large batch of chocolates, the probability of choosing one with both nuts and raisins is 0.3.1f 40% overall have nuts, what is the probability that a chocolate with

nuts will also have raisins?

Answer 1

change 0.3 to fraction which is 3/10 then substract from 1

then it will be 1-3/10 =7/10 also 0.7