Question

Shota is a dangerous fellow who likes to go rock climbing in active volcanoes. One time, when he was 30 meters below the edge of a volcano, he heard some rumbling, so he decided to climb up out of there as quickly as he could. He climbed up at a constant rate. After 4.5 seconds, he was 7.5 meters below the edge of the volcano. How fast did Shota climb? In total, how long did it take Shota to reach the edge of the volcano?

Answer 1

Shota's speed = 5 m/s

In total, it take 6 seconds to reach the edge of the volcano.

Explanation:

Given;

Total height below the edge of the volcano = 30 m

(Note that he climbed at constant rate)

After 4.5 seconds, he was 7.5 meters below the edge of the volcano.

Time = 4.5 s

Distance covered = 30 - 7.5 = 22.5 m

His speed = distance covered/time

Substituting the values;

Speed = 22.5/4.5

Speed = 5 m/s

Time needed to reach the edge;

Time = distance/speed

Speed = 5m/s

Distance = 30 m

Substituting;

Time = 30/5 = 6 seconds