Question

Consider the polynomial: StartFraction x Over 4 EndFraction – 2x5 + StartFraction x cubed Over 2 EndFraction + 1 Which polynomial represents the standard form of the original polynomial? StartFraction x cubed Over 2 EndFraction – 2x5 + StartFraction x Over 4 EndFraction + 1 –2x5 + StartFraction x cubed Over 2 EndFraction + StartFraction x Over 4 EndFraction + 1 –2x5 + StartFraction x Over 4 EndFraction + StartFraction x cubed Over 2 EndFraction + 1 1 – 2x5 + StartFraction x cubed Over 2 EndFraction + StartFraction x Over 4 EndFraction

Answer 1

The correct answer is B. –2x5 + StartFraction x cubed Over 2 EndFraction + StartFraction x Over 4 EndFraction + 1

hope you have a great day :D

Answer 2

(B)
`-2x^5+(x^3)/(2)+(x)/(4)+1`

–2x5 + StartFraction x cubed Over 2 EndFraction + StartFraction x Over 4 EndFraction + 1

Explanation:

Given the polynomial:
`(x)/(4)-2x^5+(x^3)/(2)+1`

We are required to pick an equivalent polynomial which is in standard form.

A polynomial is in standard form when it is written in descending powers of x.

Therefore, rearranging the polynomial above, we have:

`-2x^5+(x^3)/(2)+(x)/(4)+1`

The correct option is B.