Answer:
20 gram of H as the greastest volume
Step-by-step explanation:
Each gas sample has the same temperature and pressure. which sample occupies the greatest volume? each gas sample has the same temperature and pressure. which sample occupies the greatest volume? 40.0 gar 20.0 gne 20.0 gh2 4.0 ghe
Given that,
40.0 g of Ar
20.0 g of Ne
20.0 g of h
24.0 g of he
The ideal gas equation ; Pv = nRT
where P is the pressure, V is the volume, R is the gas constant, T is the temperature, n is the number of mole
which is equal to
n = m / M
where m is the given mass
M is the molar mass
The given gas sample are at the same temperature and pressure,
So, the temperature, pressure and gas constant are fixed.
Therefore the volume is proportional to the given mass and molar mass
V ∝ m/M
Substitute the given mass and molar mass of given masses for comparison
No of mole of Ar = mass / molar mass
= 40 / 40 = 1 mole
No of mole of Ne = mass / molar mass
= 20 / 20 = 1 mole
No of mole of h = mass / molar mass
= 20 / 1 = 20 mole
No of mole of he = mass / molar mass
= 24 / 4 = 6 mole
Hence, 20 gram of H as the greastest volume