Answer:
Explanation:
We would set up the hypothesis test. This is a test of a single population mean since we are dealing with mean
For the null hypothesis,
µ ≤ 10
For the alternative hypothesis,
µ > 10
The inequality sign indicates that It is a right tailed.
Since the population standard deviation is not given, the distribution is a student's t.
Since n = 35,
Degrees of freedom, df = n - 1 = 35 - 1 = 34
t = (x - µ)/(s/√n)
Where
x = sample mean = 14.44
µ = population mean = 10
s = samples standard deviation = 4.45
t = (14.44 - 10)/(4.45/√35) = 5.9
We would determine the p value using the t test calculator. It becomes
p < 0.00001
Since alpha, 0.01 > than the p value, then we would reject the null hypothesis. Therefore, At a 1% level of significance, we can conclude that the true mean is greater than 10.