Question

Find [H3O+], [OH-], & pOH for a window-cleaning solution whose pH is 4.33.

Answer 1

• 
  `[H_3O^+] = 1*10^(-4.33) \ M`

• 
  `[OH^-] = 1*10^(-9.67) \ M`

• 
  `pOH = 9.67`

Step-by-step explanation:

Given;

pH of the solution = 4.33

H₃O+ is calculated as;

pH = -log[H₃O⁺]

4.33 = -log[H₃O⁺]

-4.33 = log[H₃O⁺]

10⁻⁴°³³ = [H₃O⁺]

`Thus, [H_3O^+] = 1 *10^(-4.33)` M

[OH⁻] is calculated as;

[H₃O⁺] x [OH⁻] = 10⁻¹⁴

10⁻⁴°³³ x [OH⁻] = 10⁻¹⁴

`[OH^-] = (10^(-14))/(10^(-4.33)) = 10^(-9.67)\\\\Thus, [OH^-] = 1*10^(-9.67) \ M`

pOH of the solution is calculated as;

pOH + pH = 14

pOH + 4.33 = 14

pOH = 14 - 4.33

pOH = 9.67

Thus, pOH of the solution is 9.67

Summary of the calculation:

• 
  `[H_3O^+] = 1*10^(-4.33) \ M`

• 
  `[OH^-] = 1*10^(-9.67) \ M`

• 
  `pOH = 9.67`