Question

Find the equation of the line that has the given properties. Write the equation in slope-intercept form, if possible.

Contains (3, 3); perpendicular to the line y = 2x - 1

Answer 1

y = (-1/2)x + 9/2

Explanation:

the equation of a straight line can be written as;

y = mx + c ......1

Where;

m = slope

c = intercept

For two lines to be perpendicular their slope must be opposite reciprocal of each other.

m1 × m2 = -1 .....2

Given;

The equation Contains (3, 3); and perpendicular to the line y = 2x - 1

Slope of the given equation m1 = 2

Slope of the line m2; substituting m1 to equation 2.

2 × m2 = -1

m2 = -1/2

So,

y = (-1/2)x + c

To solve for c, let's substitute the given point on the line; (3,3).

3 = (-1/2)(3) + c

3 = -3/2 + c

c = 3 + 3/2

c = 9/2

Therefore, the equation of the line that has the given properties is;

y = (-1/2)x + 9/2