Question

How many grams of silver are present in 12.044 x 1023 atoms of Ag?

Answer 1

The correct answer is 201.7 g

Step-by-step explanation:

Silver is a chemical element which symbol is Ag. From the Periodic Table, the molar mass of Ag is 100.86 g/mol. Also, we know that 1 mol of atoms is equal to 6,022 x 10²³atoms (Avogadro's number). So, we have the following relations (convertion factors):

1 mol Ag atoms = 6,022 x 10²³ atoms

1 mol Ag = 100.86 g

We use this factors and we calculate the grams og Ag as follows:

`g Ag = 12.044 x 10^(23) x (1 mol Ag)/(6.022 x 10^(23) atoms ) x (100.86 g)/(1 mol Ag)` = 201.7 g