Question

How many moles of ideal iodine gas has a volume of 1250 mL at 10 degrees C and 768 mm pressure?

Answer 1

`n=0.0564mol`

Step-by-step explanation:

Hello,

In this case, since iodine is ideal we can use the ideal gas equation to compute the moles at the given conditions, considering the following units:

`V=1250mL*(1L)/(1000mL) =1.25L\\P=768mmHg*(1atm)/(760mmHg)=1.01atm\\ T=10+273.15=283.15K`

`PV=nRT`

`n=(PV)/(RT) =(1.01atm*1.25L)/(0.082(atm*L)/(mol*K)*273.15K) \\\\n=0.0564mol`

Best regards.