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In isosceles △ABC, AB = BC and CH is an altitude. Find the perimeter of △ABC, if CH = 84 cm and m∠HBC = m∠BAC +m∠BCH

User Dan Nguyen
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2 Answers

5 votes

Final answer:

The question pertains to finding the perimeter of an isosceles triangle using given measures and angle relationships, but the provided information does not align clearly with standard geometric principles.

Step-by-step explanation:

The subject of the question involves solving a mathematical problem related to finding the perimeter of an isosceles triangle, using given measures and angle relationships.

In the given isosceles triangle ABC, with AB = BC and CH as an altitude, we can find the perimeter by using a series of geometric relationships and properties of isosceles triangles. Since the problem provides the length of the altitude (CH) and an angle relationship involving angles adjacent to CH, we can set up a trigonometric equation to find the lengths of the sides of the triangle. With these lengths, the perimeter is simply the sum of all three sides.

Unfortunately, the provided information mixes elements of a trigonometric context with another scenario that includes celestial measurements. This makes it unclear how to proceed with the specific calculations for the triangle's perimeter without additional contextual clarity. Hence, there is a need to confirm the details of the problem to provide a well-informed solution.

User Samer
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4.9k points
3 votes

Answer:

Approximately 360.3

Step-by-step explanation:

△ABC, AB = BC and CH is an altitude.

Note in isosceles triangle the two base angle are equal.

And two sides are equal.

CH = 84 cm and m∠HBC = m∠BAC +m∠BCH

So yhe base angle = 50°

The length of tthe hypotenuse , lets cal it x

Sin 50 = 84/x

X = 84/sin 50

109.65 = x

For the The base

109.65²-84²=b²/4

141 = b

Perimeter = 2*109.65 + 141

Perimeter = 360.3

Approximately 360

User Andrey Korolyov
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6.1k points