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1 vote
(x)(x2−1)

Now we can see that the (x2−1) can be further factored.
x+1
(x)(x−1)(x+1)
We now have two expressions of (x+1), one on the numerator and one on the denominator, which means we can cancel them out and simply put 1 in the numerator.
1
x(x−1)
And once we distribute the x back in the denominator, we will have:
1
x2−x
Our final answer is J,
1
x2−x
.

1 Answer

4 votes

Answer:

you already answered whatever you asked

Step-by-step explanation:

what on earth is the question

User Nargis
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