Question

1. A gas has a pressure of 799.0 mm Hg at 50.0 degrees C. What is the temperature at standard Pressure?

2. A gas has a pressure of 0.470 atm at 60.0 degrees C. What is the pressure at standard temperature?

Answer 1

1.
`T_2=307.23K=34.23\°C`

2.
`P_2=0.385atm`

Step-by-step explanation:

Hello,

1. In this case, the standard pressure is 1 atm or 760 mmHg, therefore, using the Gay-Lussac's law we can compute the corresponding temperature considering the initial 50.0 °C in absolute Kelvins:

`(T_1)/(P_1)= (T_2)/(P_2)\\\\T_2=(T_1P_2)/(P_1)=((50+273.15)K*760mmHg)/(799mmHg) \\\\T_2=307.23K=34.23\°C`

2. As well as in the previous case, we now compute the pressure at 273 K which is the standard temperature:

`(P_1)/(T_1)= (P_2)/(T_2)\\\\P_2=(P_1T_2)/(T_1)=(273K*0.47atm)/((60+273)K) \\\\P_2=0.385atm`

Best regards.