Answer:
x=4
Explanation:
Notice that the angle between side x and side 2 in the small right triangle on the left is the same angle between the sides x and (2+6 = 8) in the larger right angle triangle.
if we name the angle in question
, then we have for the small triangle on the left, the following trigonometric relationship:
![cos(\alpha)= (adj)/(hyp) \\cos(\alpha)= (2)/(x)](https://img.qammunity.org/2021/formulas/mathematics/college/5dlvx3u1jojjbvsrmg2n0w7oem4a6u22xg.png)
because in that small triangle, the side adjacent (adj) to angle
is "2" and the hypotenuse (hyp) is "x" .
We can set some similar relationship for the larger triangle, which has a hypotenuse (hyp) of length (2+6 = 8), and that has for side adjacent (adj) to the angle
side "x":
![cos(\alpha)= (adj)/(hyp) \\cos(\alpha)= (x)/(8)](https://img.qammunity.org/2021/formulas/mathematics/college/sklas4x13unuvv6pykg1c3d3f4dmy6gxfd.png)
Now, we can make both
expressions equal since they involve the same angle, and solve for "x" in the resultant formula:
![cos(\alpha) = (2)/(x) \\cos(\alpha) = (x)/(8) \\(2)/(x) =(x)/(8)\\16 = x^2](https://img.qammunity.org/2021/formulas/mathematics/college/2hdcn1aeow50qsddzky5rtvnvbwcz1s6kp.png)
therefore x is either "4" or "-4" to give 16 when squared.
We opt for the positive answer since we want a length.