Question

Question 5 (1 point)

1.50 moles of a gas has a temperature of 23 degrees C and a volume of 3.00 L. What is the pressure of the gas?

Answer 1

P=12.16 atm

Step-by-step explanation:

Using the formula of ideal gas law:

PV = nRT

P= nRT/V

n= number of moles

R= Avogadro constant = 0.0821

T= Temperature in K => ºC + 273.15 K

P= (1.50 moles)(0.0821)( 296.15 K)/ 3.00L

P= 12.15